The cyclic cations having the same number of | vedclass

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(A) Hyperconjugation is determined by the number of $\alpha$-hydrogens attached to the carbon atoms directly bonded to the positively charged carbocat

Vedclass · Accepted Answer

$A$ and $C$ Only

Vedclass · Answer

(A) Hyperconjugation is determined by the number of $\alpha$-hydrogens attached to the carbon atoms directly bonded to the positively charged carbocation center.$A$: The carbocation is bonded to two ring carbons and one methyl group. The $\alpha$-hydrogens are: $2$ (from $CH_2$ of ring) + $2$ (from $CH_2$ of ring) + $2$ (from $CH_3$) = $6 \alpha H$.$B$: The carbocation is bonded to two ring carbons and one methyl group. The $\alpha$-hydrogens are: $2$ (from $CH_2$ of ring) + $2$ (from $CH_2$ of ring) + $3$ (from $CH_3$) = $7 \alpha H$.$C$: The carbocation is bonded to two ring carbons. The $\alpha$-hydrogens are: $2$ (from $CH_2$ of ring) + $2$ (from $CH_2$ of ring) + $2$ (from $CH_2$ of ethyl group) = $6 \alpha H$.$D$: The carbocation is bonded to two ring carbons and one ethyl group. The $\alpha$-hydrogens are: $2$ (from $CH_2$ of ring) + $2$ (from $CH_2$ of ring) + $1$ (from $CH$ of ethyl group) = $5 \alpha H$.Thus, structures $A$ and $C$ have the same number of hyperconjugation ($6 \alpha H$ each).

The cyclic cations having the same number of hyperconjugation are: Choose the correct answer from the options given below:

Similar Questions

In the following resonance structures,the curved arrow indicates that electrons are shifted from:

The decreasing order of stability of the following anions is:
$(P)$ $p-OCH_3-C_6H_4-CH_2^-$
$(Q)$ $p-CHO-C_6H_4-CH_2^-$
$(R)$ $p-Cl-C_6H_4-CH_2^-$
$(S)$ $p-CH_3-C_6H_4-CH_2^-$

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$(a)$ $Cl_3CCOOH > Cl_2CHCOOH > ClCH_2COOH$
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Explain the inductive effect with a suitable example.

Which of the following does not show hyperconjugation?

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