The de-Broglie wavelength associated with a p | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The de-Broglie wavelength $\lambda$ is given by the formula $\lambda = \frac{h}{mv}$.Given: Mass $(m) = 10^{-6} \ kg$,Velocity $(v) = 10 \ ms^{-1}

Vedclass · Accepted Answer

$6.63 	imes 10^{-29} \ m$

Vedclass · Answer

(B) The de-Broglie wavelength $\lambda$ is given by the formula $\lambda = \frac{h}{mv}$.Given: Mass $(m) = 10^{-6} \ kg$,Velocity $(v) = 10 \ ms^{-1}$,and Planck's constant $(h) = 6.63 	imes 10^{-34} \ J \cdot s$.Substituting the values:$\lambda = \frac{6.63 	imes 10^{-34}}{10^{-6} 	imes 10} = \frac{6.63 	imes 10^{-34}}{10^{-5}} = 6.63 	imes 10^{-29} \ m$.Therefore,the correct option is $(B)$.

The de-Broglie wavelength associated with a particle of mass $10^{-6} \ kg$ moving with a velocity of $10 \ ms^{-1}$ is:

Similar Questions

The wavelengths of electron waves in two orbits are in the ratio $3: 5$. The ratio of the kinetic energy of the electrons will be:

The de Broglie wavelength of a tennis ball of $60 \ g$ moving with a velocity of $10 \ m/s$ is approximately

Which of the following expressions represents the de-Broglie relationship?

Calculate the mass of a photon,if its wavelength is given as $0.35 \ nm$.

If the wavelength and the distance traveled by an electron in $1 \ s$ are the same,calculate its velocity.

Vedclass Test Series

Exam Paper Generator

Online Exam Module