Which of the following expressions represents the de-Broglie relationship?
- A$h = \frac{\lambda}{mv}$
- B$\lambda = \frac{h}{mv}$
- C$\lambda = \frac{m}{hv}$
- D$\lambda = \frac{v}{mh}$
Explore More
Similar Questions
The mass of an electron is $9.1 \times 10^{-31} \ kg$. If its $K.E.$ is $3.0 \times 10^{-25} \ J$,calculate its wavelength.
Medium
View SolutionThe mass of a proton is $1.67 \times 10^{-27} \ kg$. If it is moving with a velocity of $10^3 \ m/s$,calculate its wavelength in nanometers.
Medium
View SolutionThe kinetic energy of an electron is $4.55 \times 10^{-25} \ J$. Find its wavelength.
Medium
View SolutionThe de Broglie wavelength $(\lambda)$ associated with a photoelectron varies with the frequency $(v)$ of the incident radiation as,[$v_0$ is threshold frequency]:
DifficultJEE MAIN 2019
View SolutionCan the wave nature of ordinary objects be detected? Why?
Easy
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo