The de Broglie wavelength of a particle of ma | vedclass

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Question

(A) The de Broglie wavelength $(\lambda)$ is given by the formula: $\lambda = \frac{h}{mv}$ Given: Mass $(m) = 1 \ mg = 1 	imes 10^{-6} \ kg$ Velocit

Vedclass · Accepted Answer

$6.63 	imes 10^{-29} \ m$

Vedclass · Answer

(A) The de Broglie wavelength $(\lambda)$ is given by the formula: $\lambda = \frac{h}{mv}$ Given: Mass $(m) = 1 \ mg = 1 	imes 10^{-6} \ kg$ Velocity $(v) = 10 \ m \ s^{-1}$ Planck's constant $(h) = 6.63 	imes 10^{-34} \ J \ s$ Substituting the values into the formula: $\lambda = \frac{6.63 	imes 10^{-34} \ J \ s}{(1 	imes 10^{-6} \ kg) 	imes (10 \ m \ s^{-1})}$ $\lambda = \frac{6.63 	imes 10^{-34}}{10^{-5}} \ m$ $\lambda = 6.63 	imes 10^{-29} \ m$

The de Broglie wavelength of a particle of mass $1 \ mg$ moving with a velocity of $10 \ m \ s^{-1}$ is $(h=6.63 \times 10^{-34} \ J \ s)$

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