The decay constant of a radioisotope is lambd | vedclass

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(C) The activity $A$ of a radioactive sample is given by $A = \lambda N$,where $N$ is the number of undecayed nuclei present at that time.At time $t_1

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$(A_1 - A_2) / \lambda$

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(C) The activity $A$ of a radioactive sample is given by $A = \lambda N$,where $N$ is the number of undecayed nuclei present at that time.At time $t_1$,the activity is $A_1 = \lambda N_1$,which implies $N_1 = A_1 / \lambda$.At time $t_2$,the activity is $A_2 = \lambda N_2$,which implies $N_2 = A_2 / \lambda$.The number of nuclei that have decayed during the time interval $(t_1 - t_2)$ is the difference between the number of nuclei present at time $t_1$ and time $t_2$.Number of decayed nuclei $= N_1 - N_2 = \frac{A_1}{\lambda} - \frac{A_2}{\lambda} = \frac{A_1 - A_2}{\lambda}$.

The decay constant of a radioisotope is $\lambda$. If $A_1$ and $A_2$ are its activities at times $t_1$ and $t_2$ respectively,what is the number of nuclei that have decayed during the time interval $(t_1 - t_2)$?

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