The decreasing order of acidic nature of the | vedclass

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(C) Terminal alkynes contain an $sp$ hybridized $C-H$ group that is acidic in nature. The acidity of these compounds depends on the stability of the c

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$II > I > III$

Vedclass · Answer

(C) Terminal alkynes contain an $sp$ hybridized $C-H$ group that is acidic in nature. The acidity of these compounds depends on the stability of the conjugate base formed after the removal of a proton $(H^+)$.$1.$ The $-NO_2$ group is a strong electron-withdrawing group ($-I$ and $-M$ effect). It decreases the electron density on the ring and the carbanion,thereby stabilizing the conjugate base. Thus,compound $II$ is the most acidic.$2.$ The $-NH_2$ group is an electron-donating group ($+M$ effect). It increases the electron density on the ring and the carbanion,thereby destabilizing the conjugate base. Thus,compound $III$ is the least acidic.$3.$ Compound $I$ has no substituent on the benzene ring.Therefore,the decreasing order of acidity is $II > I > III$.

The decreasing order of acidic nature of the following compounds is

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