The dependence of Gibbs free energy on pressu | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) For an isothermal process of an ideal gas,the change in Gibbs free energy is related to pressure by the equation: $\Delta G = \int_{P_1}^{P_2} V \

Vedclass · Accepted Answer

$\Delta G_T = nRT \ln \frac{P_2}{P_1}$

Vedclass · Answer

(A) For an isothermal process of an ideal gas,the change in Gibbs free energy is related to pressure by the equation: $\Delta G = \int_{P_1}^{P_2} V \, dP$. Since $PV = nRT$,we have $V = \frac{nRT}{P}$. Substituting this into the integral: $\Delta G = \int_{P_1}^{P_2} \frac{nRT}{P} \, dP = nRT \int_{P_1}^{P_2} \frac{1}{P} \, dP$. Evaluating the integral gives: $\Delta G = nRT \ln \left( \frac{P_2}{P_1} \right)$. Therefore,the correct option is $A$.

The dependence of Gibbs free energy on pressure for an isothermal process of an ideal gas is given by:

Similar Questions

$2 \, mol$ of zinc is dissolved in $HCl$ at $25 \, ^\circ C$. The work done in an open vessel is: (in $, kJ$)

What will be the value of $\Delta G$ for the melting of ice at $283 \ K$?

Which of the following conditions regarding a chemical process ensures its spontaneity at all temperatures?

If an endothermic reaction is non-spontaneous at the freezing point of water and becomes feasible at its boiling point,then:

For a certain reaction, $\Delta H = -50 \text{ kJ}$ and $\Delta S = -100 \text{ J/K}$. Find the temperature range at which the reaction is spontaneous.

Vedclass Test Series

Exam Paper Generator

Online Exam Module