The derivative of the function f(x) is tan^4 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Given that $f'(x) = 	an^4 x$ and $f(0) = 0$. We need to evaluate $\lim_{x 	o 0} \frac{f(x)}{x}$. Since $f(0) = 0$,we can write this as: $\lim_{x

Vedclass · Accepted Answer

$0$

Vedclass · Answer

(B) Given that $f'(x) = 	an^4 x$ and $f(0) = 0$. We need to evaluate $\lim_{x 	o 0} \frac{f(x)}{x}$. Since $f(0) = 0$,we can write this as: $\lim_{x 	o 0} \frac{f(x) - 0}{x - 0} = \lim_{x 	o 0} \frac{f(x) - f(0)}{x - 0}$. By the definition of the derivative,this limit is equal to $f'(0)$. Since $f'(x) = 	an^4 x$,we have $f'(0) = 	an^4(0) = 0^4 = 0$. Therefore,the limit is $0$.

The derivative of the function $f(x)$ is $\tan^4 x$. If $f(0) = 0$,then $\lim_{x \to 0} \frac{f(x)}{x}$ is equal to

Similar Questions

Find the derivative of the following function from first principles: $\cos \left(x-\frac{\pi}{8}\right)$

Find the derivative of $\cos x$ from first principle.

Find the derivative at $x=2$ of the function $f(x)=3x$.

Find the derivative of the function $(ax + b)^n$ with respect to $x$,where $a$ and $b$ are fixed non-zero constants and $n$ is an integer.

Find the derivative of $f(x) = x$ at $x = 1$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module