The descending order of acidity for the follo | vedclass

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(D) The acidity of carboxylic acids is determined by the stability of the carboxylate anion formed after the loss of a proton. Electron-withdrawing gr

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$B > D > C > E > A$

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(D) The acidity of carboxylic acids is determined by the stability of the carboxylate anion formed after the loss of a proton. Electron-withdrawing groups ($-I$ effect) increase acidity by stabilizing the negative charge,while electron-donating groups ($+I$ effect) decrease acidity.$1$. $B$ $(F_3C-COOH)$: Contains three highly electronegative fluorine atoms,exerting a strong $-I$ effect,making it the most acidic.$2$. $D$ $(FCH_2-COOH)$: Contains one fluorine atom,which has a stronger $-I$ effect than chlorine or bromine.$3$. $C$ $(ClCH_2-COOH)$: Contains a chlorine atom,which has a weaker $-I$ effect than fluorine but stronger than bromine.$4$. $E$ $(BrCH_2-COOH)$: Contains a bromine atom,which has the weakest $-I$ effect among the halogens listed.$5$. $A$ $(CH_3COOH)$: Contains a methyl group,which exerts a $+I$ effect,destabilizing the carboxylate anion and making it the least acidic.Thus,the descending order of acidity is $B > D > C > E > A$.

The descending order of acidity for the following carboxylic acids is:
$A.$ $CH_3COOH$
$B.$ $F_3C-COOH$
$C.$ $ClCH_2-COOH$
$D.$ $FCH_2-COOH$
$E.$ $BrCH_2-COOH$
Choose the correct answer from the options given below:

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The descending order of acidity for the following carboxylic acids is:$A.$ $CH_3COOH$$B.$ $F_3C-COOH$$C.$ $ClCH_2-COOH$$D.$ $FCH_2-COOH$$E.$ $BrCH_2-COOH$Choose the correct answer from the options given below: