The diagram shows a circuit used in an experiment to determine the $emf$ $(E)$ and internal resistance $(r)$ of the cell $C$. $A$ graph was plotted of the potential difference $V$ between the terminals of the cell against the current $I$,which was varied by adjusting the rheostat. The graph is shown on the right; $x$ and $y$ are the intercepts of the graph with the axes as shown. What is the internal resistance of the cell?
- A$x$
- B$y$
- C$x/y$
- D$y/x$
Explore More
Similar Questions
The readings of the voltmeter and ammeter in the circuit shown in the diagram are respectively
Refer to the circuit shown. What will be the total power dissipation in the circuit if $P$ is the power dissipated in $R_1$ (in $P$)? It is given that $R_2 = 4 R_1$ and $R_3 = 12 R_1$.
Medium
View SolutionWhen two identical resistors are connected in series to an ideal cell,the current through each resistor is $2 \ A$. If the resistors are connected in parallel to the same cell,the current through each resistor is: (in $A$)
$A$ current of $2\,A$ flows in a system of conductors as shown. The potential difference $(V_A - V_B)$ will be ............ $V$.
Easy
View SolutionTwo resistances of $400 \Omega$ and $800 \Omega$ are connected in series with a $6 \text{ V}$ battery of negligible internal resistance. $A$ voltmeter of resistance $10000 \Omega$ is used to measure the potential difference across the $400 \Omega$ resistor. The error in the measurement of potential difference in volts is approximately:
DifficultTS EAMCET 2003
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo