The diagram shows the change x in the length | vedclass

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(A) From Hooke's Law,$F = kx$,where $k$ is the force constant of the wire. The slope of the $F-x$ graph is equal to the force constant $k = \frac{YA}{

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$T_1 > T_2$

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(A) From Hooke's Law,$F = kx$,where $k$ is the force constant of the wire. The slope of the $F-x$ graph is equal to the force constant $k = \frac{YA}{L}$,where $Y$ is Young's modulus,$A$ is the area of cross-section,and $L$ is the length of the wire.The elasticity (Young's modulus $Y$) of a material generally decreases as the temperature increases.In the given graph,the slope of the line for $T_2$ is greater than the slope of the line for $T_1$ (i.e.,$	ext{slope}_{T_2} > 	ext{slope}_{T_1}$).Since a higher slope corresponds to a higher Young's modulus $(Y)$,and a higher $Y$ corresponds to a lower temperature,it follows that $T_2  T_2$.

The diagram shows the change $x$ in the length of a thin uniform wire caused by the application of force $F$ at two different temperatures $T_1$ and $T_2$. The variations shown suggest that

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