The diameter of a circular garden is 210 ,m. | vedclass

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Question

(C) Radius of the garden $r_2 = \frac{	ext{diameter}}{2} = \frac{210}{2} = 105 \,m$.Radius of the garden excluding the path $r_1 = 105 - 7 = 98 \,m$.

Vedclass · Accepted Answer

$4466$

Vedclass · Answer

(C) Radius of the garden $r_2 = \frac{	ext{diameter}}{2} = \frac{210}{2} = 105 \,m$.Radius of the garden excluding the path $r_1 = 105 - 7 = 98 \,m$.Area of the path in the form of a circular ring is given by the difference between the area of the outer circle and the inner circle.Area of the path $= \pi r_2^2 - \pi r_1^2$$= \pi(r_2^2 - r_1^2)$$= \pi(r_2 + r_1)(r_2 - r_1)$$= \frac{22}{7} 	imes (105 + 98) 	imes (105 - 98)$$= \frac{22}{7} 	imes 203 	imes 7$$= 22 	imes 203$$= 4466 \,m^2$.

The diameter of a circular garden is $210 \,m$. Inside it,all along the boundary,there is a path of uniform width $7 \,m$. Then,the area of the path is $\ldots \ldots \ldots \ldots \,m^2$.

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