The diameter of the objective of a telescope | vedclass

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Question

(A) The resolving limit $(d	heta)$ of a telescope is given by the formula:$d	heta = \frac{1.22 \lambda}{a}$Where $\lambda$ is the wavelength of ligh

Vedclass · Accepted Answer

$5.54 	imes 10^{-7} \ rad$

Vedclass · Answer

(A) The resolving limit $(d	heta)$ of a telescope is given by the formula:$d	heta = \frac{1.22 \lambda}{a}$Where $\lambda$ is the wavelength of light and $a$ is the diameter of the objective lens.Given:$\lambda = 4538 \ \mathring A = 4538 	imes 10^{-10} \ m$$a = 1 \ m$Substituting the values:$d	heta = \frac{1.22 	imes 4538 	imes 10^{-10}}{1}$$d	heta = 5536.36 	imes 10^{-10} \ rad$$d	heta \approx 5.54 	imes 10^{-7} \ rad$Thus,the correct option is $A$.

The diameter of the objective of a telescope is $1 \ m$. Its resolving limit for light of wavelength $4538 \ \mathring A$ will be:

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