The diameter of the objective of a telescope is $3.6 \ m$. The limit of resolution of the telescope for a light of wavelength $540 \ nm$ is
- A$1.22 \times 10^{-7} \ rad$
- B$1.83 \times 10^{-7} \ rad$
- C$0.61 \times 10^{-7} \ rad$
- D$3.76 \times 10^{-7} \ rad$
Explore More
Similar Questions
If the aperture of a telescope is decreased,the resolving power will:
The diameter of the objective of a telescope is $10 \, cm$. There are two objects at a distance of $1 \, km$ from it. What should be the minimum distance between these two objects so that their images are seen as separate by this telescope? The wavelength of light is $5000 \, \mathring{A}$.
Difficult
View SolutionAssertion: The resolving power of a telescope is more if the diameter of the objective lens is more.
Reason: Objective lens of large diameter collects more light.
Reason: Objective lens of large diameter collects more light.
The diameter of the objective of a telescope is $200 \text{ cm}$. What is the resolving power of the telescope? Take the wavelength of light $\lambda = 5000 \text{ \AA}$.
$A$ person is observing a bacteria through a compound microscope. For better analysis and to improve the resolving power,he should:
Vedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo