The diffraction pattern of light of wavelengt | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The width of the $n^{	ext{th}}$ secondary maxima in a single-slit diffraction pattern is given by $\beta = \frac{\lambda D}{a}$,where $\lambda$ i

Vedclass · Accepted Answer

$2 \ mm$

Vedclass · Answer

(A) The width of the $n^{	ext{th}}$ secondary maxima in a single-slit diffraction pattern is given by $\beta = \frac{\lambda D}{a}$,where $\lambda$ is the wavelength,$D$ is the distance of the screen (focal length of the lens),and $a$ is the slit width.Given:$\lambda = 400 \ nm = 400 	imes 10^{-9} \ m$$a = 0.2 \ mm = 0.2 	imes 10^{-3} \ m$$D = 100 \ cm = 1 \ m$Substituting the values:$	ext{Width} = \frac{400 	imes 10^{-9} \ m 	imes 1 \ m}{0.2 	imes 10^{-3} \ m}$$= \frac{400}{0.2} 	imes 10^{-6} \ m$$= 2000 	imes 10^{-6} \ m$$= 2 	imes 10^{-3} \ m = 2 \ mm$.

The diffraction pattern of light of wavelength $400 \ nm$ diffracting from a slit of width $0.2 \ mm$ is focused on the focal plane of a convex lens of focal length $100 \ cm$. The width of the $1^{\text{st}}$ secondary maxima will be:

Similar Questions

In a single slit diffraction, the slit is illuminated with light of wavelength $6000 \text{ Å}$. If the slit were illuminated by a light of wavelength $\lambda$ the angular width of the central maximum decreases by $30 \%$. Then $\lambda$ is (in $\text{ Å}$)

Light of wavelength $\lambda$ is incident on a single slit of width $a$,and the distance between the slit and the screen is $D$. In the diffraction pattern,if the slit width is equal to the width of the central maximum,then $D=$

$A$ slit of width $d$ is illuminated by light of wavelength $\lambda$. The angular width of the central maximum is:

The angular deviation of the $5^{th}$ order dark fringe is $12^{\circ}$ in a single slit experiment. If the width of the slit is $9 \mu m$, then the wavelength of the incident light is: (in $Å$)

Light of wavelength $5000 \, \mathring{A}$ is incident on a single slit such that the first minima is formed at a distance $5 \, mm$ from the centre. If the screen is placed $2 \, m$ away,then find the width of the slit in $mm$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module