The dimension of $\frac{B^{2}}{2 \mu_{0}}$,where $B$ is magnetic field and $\mu_{0}$ is the magnetic permeability of vacuum,is

  • A
    $M L^{-1} T^{-2}$
  • B
    $M L^{2} T^{-1}$
  • C
    $M L T^{-2}$
  • D
    $M L^{2} T^{-2}$

Explore More

Similar Questions

What is the dimensional formula of the spring constant $k$?

$A$ unitless quantity?

The potential energy of a particle varies with distance $x$ from a fixed origin as $V = \frac{A\sqrt{x}}{x + B}$,where $A$ and $B$ are constants. The dimensions of $AB$ are

Match List-$I$ with List-$II$.
List-$I$ List-$II$
$(A)$ Angular momentum $(I)$ $[ML^2T^{-1}]$
$(B)$ Torque $(II)$ $[ML^2T^{-2}]$
$(C)$ Stress $(III)$ $[ML^{-1}T^{-2}]$
$(D)$ Pressure gradient $(IV)$ $[ML^{-2}T^{-2}]$

Choose the correct answer from the options given below:

If $G$ is the universal gravitational constant and $g$ is the acceleration due to gravity,then the dimensions of $\frac{G}{g}$ will be ...................

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo