The dissociation constants of two acids HA_1 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The relative strength of two acids is given by the ratio of their degrees of dissociation,which is equal to the square root of the ratio of their

Vedclass · Accepted Answer

$4:1$

Vedclass · Answer

(B) The relative strength of two acids is given by the ratio of their degrees of dissociation,which is equal to the square root of the ratio of their dissociation constants: $\frac{	ext{Strength}_1}{	ext{Strength}_2} = \sqrt{\frac{K_{a_1}}{K_{a_2}}}$ Given $K_{a_1} = 3.14 	imes 10^{-4}$ and $K_{a_2} = 1.96 	imes 10^{-5}$. $\frac{	ext{Strength}_1}{	ext{Strength}_2} = \sqrt{\frac{3.14 	imes 10^{-4}}{1.96 	imes 10^{-5}}} = \sqrt{\frac{31.4 	imes 10^{-5}}{1.96 	imes 10^{-5}}} \approx \sqrt{16} = 4$. Thus,the relative strength is $4:1$.

The dissociation constants of two acids $HA_1$ and $HA_2$ are $3.14 \times 10^{-4}$ and $1.96 \times 10^{-5}$ respectively. The relative strength of the acids will be approximately:

Similar Questions

The species among the following,which can act as an acid and a base is

The correct order of basic strength of the following compounds is:
$(I)$ $KOH$
$(II)$ $Zn(OH)_2$
$(III)$ $HNO_3$
$(IV)$ $Ca(OH)_2$

Which of the following compounds has the highest value of dissociation constant $(K_a)$?

Which gas should not be collected over water because of its high solubility in water?

Which of the following is the strongest conjugate base?

Vedclass Test Series

Exam Paper Generator

Online Exam Module