The distance between A(2,4) and B(-3,4) is... | vedclass

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(A) The distance $d$ between two points $(x_1, y_1)$ and $(x_2, y_2)$ is given by the formula: $d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$.Given points

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$5$

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(A) The distance $d$ between two points $(x_1, y_1)$ and $(x_2, y_2)$ is given by the formula: $d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$.Given points are $A(2, 4)$ and $B(-3, 4)$.Here,$x_1 = 2, y_1 = 4$ and $x_2 = -3, y_2 = 4$.Substituting these values into the formula:$d = \sqrt{(-3 - 2)^2 + (4 - 4)^2}$$d = \sqrt{(-5)^2 + (0)^2}$$d = \sqrt{25 + 0}$$d = \sqrt{25} = 5$.Therefore,the distance between the points is $5$ units.

The distance between $A(2,4)$ and $B(-3,4)$ is............

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