The distance between the points $(0, 5)$ and $(-5, 0)$ is

  • A
    $5$
  • B
    $10$
  • C
    $5 \sqrt{2}$
  • D
    $2 \sqrt{5}$

Explore More

Similar Questions

Find the area of the triangle whose vertices are $(-8, 4), (-6, 6)$ and $(-3, 9).$

$A$ line intersects the $y$-axis and $x$-axis at the points $P$ and $Q$,respectively. If $(2, -5)$ is the mid-point of $PQ$,then the coordinates of $P$ and $Q$ are,respectively:

In which ratio and at which point does the $Y-$ axis divide the line segment joining $A(-2, 3)$ and $B(3, 0)$ from $A$?

If the area of the triangle having the vertices $A (a, 5), B (6, 7), C (2, 3)$ is $10$,then find $a$.

Using the distance formula,show that $(4, 3)$,$(5, 1)$,and $(1, 9)$ are collinear.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo