The distance of an object from the pole of a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) For a concave mirror,the radius of curvature $R$ is equal to $2f$. The object distance $u = -R = -2f$. Using the mirror formula $\frac{1}{v} + \fr

Vedclass · Accepted Answer

real

Vedclass · Answer

(A) For a concave mirror,the radius of curvature $R$ is equal to $2f$. The object distance $u = -R = -2f$. Using the mirror formula $\frac{1}{v} + \frac{1}{u} = \frac{1}{f}$,we substitute $u = -2f$: $\frac{1}{v} + \frac{1}{-2f} = \frac{1}{-f}$ $\frac{1}{v} = \frac{1}{2f} - \frac{1}{f} = -\frac{1}{2f}$ Thus,$v = -2f = -R$. The image is formed at the same position as the object (the centre of curvature). Since the image is formed in front of the mirror,it is real and inverted,and its size is equal to the size of the object.

The distance of an object from the pole of a concave mirror is equal to its radius of curvature. The image must be:

Similar Questions

An object of length $6 \ cm$ is placed on the principal axis of a concave mirror of focal length $f$ at a distance of $4f$. The length of the image will be......$cm$.

An object is placed $40\;cm$ from a concave mirror of focal length $20\;cm.$ The image formed is

In an experiment to find the focal length of a concave mirror,a graph is drawn between the magnitudes of $u$ and $v$. The graph looks like:

Distance between an object and its three times magnified real image is $40 \ cm$. The focal length of the mirror used is . . . . . . $cm$.

An object of length $6 \ cm$ is placed at a distance of $4f$ on the principal axis of a concave mirror of focal length $f$. The length of the image will be ......$cm$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module