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(A) The coordinates of the point $P$ are $(a, b, c)$.To find the distance of point $P$ from the $x$-axis,we project the point onto the $x$-axis.The pr

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$\sqrt{b^{2}+c^{2}}$

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(A) The coordinates of the point $P$ are $(a, b, c)$.To find the distance of point $P$ from the $x$-axis,we project the point onto the $x$-axis.The projection of point $P(a, b, c)$ on the $x$-axis is the point $A(a, 0, 0)$.The distance $d$ between two points $(x_1, y_1, z_1)$ and $(x_2, y_2, z_2)$ is given by the formula $d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2 + (z_2-z_1)^2}$.Substituting the coordinates of $P(a, b, c)$ and $A(a, 0, 0)$:$d = \sqrt{(a-a)^2 + (0-b)^2 + (0-c)^2}$$d = \sqrt{0^2 + (-b)^2 + (-c)^2}$$d = \sqrt{b^2 + c^2}$.

The distance of the point $P(a, b, c)$ from the $x$-axis is

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