The distance of the point (-2, 3) from the li | vedclass

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Question

(A) The distance $d$ of a point $(x_1, y_1)$ from the line $Ax + By + C = 0$ is given by the formula $d = \frac{|Ax_1 + By_1 + C|}{\sqrt{A^2 + B^2}}$.

Vedclass · Accepted Answer

$5\sqrt{2}$

Vedclass · Answer

(A) The distance $d$ of a point $(x_1, y_1)$ from the line $Ax + By + C = 0$ is given by the formula $d = \frac{|Ax_1 + By_1 + C|}{\sqrt{A^2 + B^2}}$.Given the point $(-2, 3)$ and the line $x - y - 5 = 0$,we have $A = 1, B = -1, C = -5, x_1 = -2, y_1 = 3$.Substituting these values into the formula:$d = \frac{|(1)(-2) + (-1)(3) - 5|}{\sqrt{1^2 + (-1)^2}}$$d = \frac{|-2 - 3 - 5|}{\sqrt{1 + 1}}$$d = \frac{|-10|}{\sqrt{2}}$$d = \frac{10}{\sqrt{2}} = 5\sqrt{2}$.

The distance of the point $(-2, 3)$ from the line $x - y - 5 = 0$ is

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