The Earth's magnetic induction at a certain p | vedclass

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(B) The magnetic field at the center of a circular loop is given by $B = \frac{\mu_0 I}{2R}$.Given,$B = 7 	imes 10^{-5} \ Wb/m^2$ and $R = 5 \ cm = 0

Vedclass · Accepted Answer

$5.6$

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(B) The magnetic field at the center of a circular loop is given by $B = \frac{\mu_0 I}{2R}$.Given,$B = 7 	imes 10^{-5} \ Wb/m^2$ and $R = 5 \ cm = 0.05 \ m$.We know that $\frac{\mu_0}{4\pi} = 10^{-7} \ T \cdot m/A$,so $\mu_0 = 4\pi 	imes 10^{-7} \ T \cdot m/A$.Substituting the values into the formula:$7 	imes 10^{-5} = \frac{4\pi 	imes 10^{-7} 	imes I}{2 	imes 0.05}$$7 	imes 10^{-5} = \frac{2\pi 	imes 10^{-7} 	imes I}{0.05}$$I = \frac{7 	imes 10^{-5} 	imes 0.05}{2 	imes 3.14159 	imes 10^{-7}}$$I = \frac{0.35 	imes 10^{-5}}{6.283 	imes 10^{-7}} = \frac{35}{6.283} \approx 5.57 \ A \approx 5.6 \ A$.

The Earth's magnetic induction at a certain point is $7 \times 10^{-5} \ Wb/m^2$. This is to be annulled by the magnetic induction at the center of a circular conducting loop of radius $5 \ cm$. The required current in the loop is......$A$

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