The electric and the magnetic field,associated with an electromagnetic wave propagating along the $+z$-axis,can be represented by

  • A
    $\vec{E} = E_0 \hat{i}, \vec{B} = B_0 \hat{j}$
  • B
    $\vec{E} = E_0 \hat{k}, \vec{B} = B_0 \hat{i}$
  • C
    $\vec{E} = E_0 \hat{j}, \vec{B} = B_0 \hat{i}$
  • D
    $\vec{E} = E_0 \hat{j}, \vec{B} = B_0 \hat{k}$

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$A$ $27\, mW$ laser beam has a cross-sectional area of $10\, mm^2$. The magnitude of the maximum electric field in this electromagnetic wave is given by: $........\, kV/m$. [Given permittivity of free space $\epsilon_0 = 9 \times 10^{-12}\, SI\, units$, speed of light $c = 3 \times 10^8\, m/s$]

An electromagnetic wave with frequency $\omega$ and wavelength $\lambda$ travels in the $+y$ direction. Its magnetic field is along the $+x$ axis. The vector equation for the associated electric field (of amplitude $E_0$) is:

Dimension of $\frac{1}{\mu_0 \varepsilon_0}$ should be equal to

The electric field $(E)$ and magnetic field $(B)$ of an electromagnetic wave passing through vacuum are given by
$E = E_0 \sin (kx - \omega t)$
$B = B_0 \sin (kx - \omega t)$
Then the correct statement among the following is

Electromagnetic waves with frequencies ranging from $2\,\text{MHz}$ to $30\,\text{MHz}$ are propagated by:

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