The electric field component of an electromag | vedclass

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(B) The given equation is of the form $\vec E = E_0 \cos(ky + \omega t)\hat i$.Comparing this with the standard wave equation,the wave propagates in t

Vedclass · Accepted Answer

$-\hat j, 3.5 \ m$

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(B) The given equation is of the form $\vec E = E_0 \cos(ky + \omega t)\hat i$.Comparing this with the standard wave equation,the wave propagates in the direction of $-y$,which is represented by the unit vector $-\hat j$.The wave number $k$ is given as $1.8 \ rad/m$.The wavelength $\lambda$ is calculated using the formula $\lambda = \frac{2\pi}{k}$.Substituting the value of $k$: $\lambda = \frac{2 	imes 3.14159}{1.8} \approx 3.49 \ m$,which rounds to $3.5 \ m$.Therefore,the direction of propagation is $-\hat j$ and the wavelength is $3.5 \ m$.

The electric field component of an electromagnetic wave in vacuum is given as $\vec E = 3\cos(1.8y + 5.4 \times 10^8 t)\hat i$. Its direction of propagation and wavelength are:

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