The electron affinity values are negative for | vedclass

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(D) Electron affinity is the energy released when an electron is added to a neutral gaseous atom or ion.$A$. $Be (2s^2)$ has a stable fully-filled con

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$A, B$ and $C$ only

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(D) Electron affinity is the energy released when an electron is added to a neutral gaseous atom or ion.$A$. $Be (2s^2)$ has a stable fully-filled configuration. Adding an electron is unfavorable,making the electron affinity negative (energy must be supplied).$B$. $N (2s^2 2p^3)$ has a stable half-filled configuration. Adding an electron is unfavorable,making the electron affinity negative.$C$. $O^{-} + e^{-} \rightarrow O^{2-}$. Adding an electron to a negatively charged ion $(O^{-})$ experiences strong inter-electronic repulsion,making the process endothermic (negative electron affinity).$D$. $Na (3s^1)$ has a low energy orbital available. Adding an electron releases energy (positive electron affinity).$E$. $Al (3s^2 3p^1)$ has an available $3p$ orbital. Adding an electron releases energy (positive electron affinity).Therefore,the processes $A, B,$ and $C$ have negative electron affinity values.

The electron affinity values are negative for:
$A$. $Be \rightarrow Be^{-}$
$B$. $N \rightarrow N^{-}$
$C$. $O^{-} \rightarrow O^{2-}$
$D$. $Na \rightarrow Na^{-}$
$E$. $Al \rightarrow Al^{-}$
Choose the most appropriate answer from the options given below:

Similar Questions

In which of the following,elements are arranged in the correct order of their electron gain enthalpies?

In which of the following processes is the least energy required?

Which of the following represents the correct order of electron gain enthalpy (electron affinity) for halogens?

The increasing order of electron affinity for the given electronic configurations of elements is:
$I. 1s^2 2s^2 2p^6 3s^2 3p^5$
$II. 1s^2 2s^2 2p^3$
$III. 1s^2 2s^2 2p^5$
$IV. 1s^2 2s^2 2p^6 3s^1$

Electron affinity depends on

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The electron affinity values are negative for:$A$. $Be \rightarrow Be^{-}$$B$. $N \rightarrow N^{-}$$C$. $O^{-} \rightarrow O^{2-}$$D$. $Na \rightarrow Na^{-}$$E$. $Al \rightarrow Al^{-}$Choose the most appropriate answer from the options given below: