The energy of a radiation of wavelength 8000 | vedclass

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(B) The energy of a photon is given by the formula $E = \frac{hc}{\lambda}$,where $h$ is Planck's constant,$c$ is the speed of light,and $\lambda$ is

Vedclass · Accepted Answer

$E_1 = 2E_2$

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(B) The energy of a photon is given by the formula $E = \frac{hc}{\lambda}$,where $h$ is Planck's constant,$c$ is the speed of light,and $\lambda$ is the wavelength.From this relation,we can see that $E \propto \frac{1}{\lambda}$.Therefore,the ratio of the energies is $\frac{E_1}{E_2} = \frac{\lambda_2}{\lambda_1}$.Given $\lambda_1 = 8000 \ \mathring{A}$ and $\lambda_2 = 16000 \ \mathring{A}$.Substituting these values,we get $\frac{E_1}{E_2} = \frac{16000}{8000} = 2$.Thus,$E_1 = 2E_2$.

The energy of a radiation of wavelength $8000 \ \mathring{A}$ is $E_1$ and energy of a radiation of wavelength $16000 \ \mathring{A}$ is $E_2$. What is the relation between these two?

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