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(B) The initial energy stored in the capacitor is $U = \frac{1}{2}CV^2$,where $C$ is the capacitance and $V$ is the potential difference.When an uncha

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$\frac{U}{4}$

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(B) The initial energy stored in the capacitor is $U = \frac{1}{2}CV^2$,where $C$ is the capacitance and $V$ is the potential difference.When an uncharged capacitor of the same capacity $C$ is connected in parallel,the total charge $Q = CV$ is redistributed between the two capacitors.Since the capacitors are in parallel,the new potential difference $V'$ across each capacitor is given by $V' = \frac{Q}{C_{eq}} = \frac{CV}{C + C} = \frac{V}{2}$.The new energy $U'$ stored in each capacitor is $U' = \frac{1}{2}C(V')^2$.Substituting $V' = \frac{V}{2}$,we get $U' = \frac{1}{2}C(\frac{V}{2})^2 = \frac{1}{2}C(\frac{V^2}{4}) = \frac{1}{4}(\frac{1}{2}CV^2) = \frac{U}{4}$.

The energy stored in a capacitor is $U$. If an uncharged capacitor of the same capacity is connected in parallel with it,then the energy stored in each capacitor is:

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