The enthalpy of vaporization of benzene is +3 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The enthalpy of vaporization $(\Delta H_{vap})$ is $+35.3 \ kJ/mol = +35300 \ J/mol$.
The boiling point $(T)$ is $80^{\circ} C = 80 + 273 = 353 \

Vedclass · Accepted Answer

$-100 \ J/mol \cdot K$

Vedclass · Answer

(A) The enthalpy of vaporization $(\Delta H_{vap})$ is $+35.3 \ kJ/mol = +35300 \ J/mol$.
The boiling point $(T)$ is $80^{\circ} C = 80 + 273 = 353 \ K$.
For the transition of liquid to vapour,the entropy change is $\Delta S_{vap} = \frac{\Delta H_{vap}}{T} = \frac{35300 \ J/mol}{353 \ K} = +100 \ J/mol \cdot K$.
The question asks for the entropy change in the transition of vapour to liquid (condensation),which is the reverse process.
Therefore,$\Delta S_{cond} = -\Delta S_{vap} = -100 \ J/mol \cdot K$.

The enthalpy of vaporization of benzene is $+35.3 \ kJ/mol$ at its boiling point,$80^{\circ} C$. The entropy change in the transition of vapour to liquid at its boiling point is

Similar Questions

Which of the following equations indicates an increase in entropy?

When a solid is converted into liquid,entropy

The entropy change involved in the conversion of $1 \, \text{mole}$ of liquid water at $373 \, K$ to vapour at the same temperature will be $[\Delta H_{vap} = 2.257 \, kJ/g]$. (in $, kJ/K$)

The increase in entropy in $J K^{-1}$ of a substance when it absorbs $1 \ kJ$ of heat energy at $3 \ K$ is

For which one of the following reactions is the entropy change positive?

Vedclass Test Series

Exam Paper Generator

Online Exam Module