The equation 2x^{2}+5xy-12y^{2}=0 represents | vedclass

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(B) The given equation is $2x^{2}+5xy-12y^{2}=0$.Factorizing the quadratic expression:$2x^{2}+8xy-3xy-12y^{2}=0$$2x(x+4y)-3y(x+4y)=0$$(x+4y)(2x-3y)=0$

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pair of non-perpendicular intersecting straight lines

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(B) The given equation is $2x^{2}+5xy-12y^{2}=0$.Factorizing the quadratic expression:$2x^{2}+8xy-3xy-12y^{2}=0$$2x(x+4y)-3y(x+4y)=0$$(x+4y)(2x-3y)=0$This implies the two lines are $x+4y=0$ and $2x-3y=0$.Comparing the equation with the general form $ax^{2}+2hxy+by^{2}=0$, we get $a=2$ and $b=-12$.The condition for perpendicular lines is $a+b=0$.Here, $a+b = 2 + (-12) = -10 
eq 0$.Since $a+b 
eq 0$, the lines are not perpendicular.Therefore, the equation represents a pair of non-perpendicular intersecting straight lines.

The equation $2x^{2}+5xy-12y^{2}=0$ represents a

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