The equation _{Z}X^{A} to _{Z+1}Y^{A} + _{-1} | vedclass

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Question

(A) In the given nuclear reaction,$_{Z}X^{A} 	o _{Z+1}Y^{A} + _{-1}e^{0} + \bar{
u}$,the atomic number of the daughter nucleus increases by $1$ $(Z+

Vedclass · Accepted Answer

$\beta^{-}$-emission

Vedclass · Answer

(A) In the given nuclear reaction,$_{Z}X^{A} 	o _{Z+1}Y^{A} + _{-1}e^{0} + \bar{
u}$,the atomic number of the daughter nucleus increases by $1$ $(Z+1)$,while the mass number $A$ remains constant.This process involves the emission of an electron $(_{-1}e^{0})$ and an antineutrino $(\bar{
u})$.This is the characteristic process of $\beta^{-}$-decay,where a neutron inside the nucleus converts into a proton,emitting an electron and an antineutrino.Therefore,the correct option is $A$.

The equation $_{Z}X^{A} \to _{Z+1}Y^{A} + _{-1}e^{0} + \bar{\nu}$ represents:

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