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(B) Let the original nucleus be ${ }_{Z} X^{A}$.When one $\alpha$ particle $({ }_{2} He^{4})$ is emitted,the nucleus becomes ${ }_{Z-2} Y^{A-4}$.When

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one $\alpha$ and two $\beta$

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(B) Let the original nucleus be ${ }_{Z} X^{A}$.When one $\alpha$ particle $({ }_{2} He^{4})$ is emitted,the nucleus becomes ${ }_{Z-2} Y^{A-4}$.When one $\beta^{-}$ particle $({ }_{-1} e^{0})$ is emitted,the atomic number increases by $1$ $(Z-2+1 = Z-1)$.When two $\beta^{-}$ particles are emitted,the atomic number increases by $2$ $(Z-2+2 = Z)$.Thus,the final nucleus is ${ }_{Z} X^{A-4}$,which is an isotope of the original nucleus ${ }_{Z} X^{A}$ because they have the same atomic number $Z$ but different mass numbers.

An isotope of the original nucleus can be formed in a radioactive decay,with the emission of which of the following particles?

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