Identify the particle x in the following reac | vedclass

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Question

(C) The given nuclear reaction is: ${}_3^7Li + {}_1^1p 	o {}_4^8Be + x$.According to the law of conservation of mass number:$7 + 1 = 8 + A_x \Rightar

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gamma photon

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(C) The given nuclear reaction is: ${}_3^7Li + {}_1^1p 	o {}_4^8Be + x$.According to the law of conservation of mass number:$7 + 1 = 8 + A_x \Rightarrow A_x = 0$.According to the law of conservation of atomic number (charge):$3 + 1 = 4 + Z_x \Rightarrow Z_x = 0$.$A$ particle with mass number $0$ and atomic number $0$ is a gamma photon $(\gamma)$.Therefore,the correct option is $C$.

Identify the particle $x$ in the following reaction: ${}_3^7Li(p, x){}_4Be^8$,where $p$ is a proton.

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