What happens to the mass number and atomic number of an element when it emits $\gamma$-radiation?

  • A
    Mass number increases by four and atomic number increases by two.
  • B
    Mass number decreases by four and atomic number decreases by two.
  • C
    Mass number and atomic number remain unchanged.
  • D
    Mass number remains unchanged while atomic number decreases by one.

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Similar Questions

An element $X$ decays into element $Z$ by a two-step process:
$X \rightarrow Y + 4e$
$Y \rightarrow Z + 2e^{-}$
Then:

The equation $_{Z}X^{A} \to _{Z+1}Y^{A} + _{-1}e^{0} + \bar{\nu}$ represents:

Which of the following interactions is responsible for beta decay?

$A$ radioactive nucleus decays as follows:
$X \xrightarrow{\alpha} X_1 \xrightarrow{\beta} X_2 \xrightarrow{\alpha} X_3 \xrightarrow{\gamma} X_4$
If the atomic number and the mass number of $X$ are $72$ and $180$ respectively,then the mass number and atomic number of $X_4$ are:

$\beta$-decay means emission of electron from

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