The equation of a circle which touches the $x$-axis and whose centre is $(1, 2)$ is

  • A
    $(x-2)^2+(y-1)^2=4$
  • B
    $(x-1)^2+(y-2)^2=4$
  • C
    $(x-1)^2+(y+2)^2=4$
  • D
    $(x+2)^2+(y-1)^2=4$

Explore More

Similar Questions

If a circle of radius $3$ passes through the point $(7,3)$ and has its centre on the line $x-y-1=0$,then its equation among the following is

$A$ circle has a radius of $3$ units and its centre lies on the line $y = x - 1$. If the circle passes through the point $(7, 3)$,what is its equation?

Find the equation of the circle passing through the foci of the ellipse $\frac{x^2}{16} + \frac{y^2}{9} = 1$ and having its center at $(0, 3)$.

Difficult
View Solution

The equation of the circle passing through the foci of the ellipse $\frac{x^2}{16} + \frac{y^2}{9} = 1$ and having its centre at $(0, 3)$ is

Find the radius and center of the circle $2x^2 + 2y^2 = 3x - 5y + 7$.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo