The equation of a circle with center at (-2, | vedclass

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(B) The circumference of the circle is $4 \pi$. Since the circumference is given by $2 \pi r = 4 \pi$,we have $r = 2$. The equation of a circle with c

Vedclass · Accepted Answer

$x^2+y^2+4x-6y+9=0$

Vedclass · Answer

(B) The circumference of the circle is $4 \pi$. Since the circumference is given by $2 \pi r = 4 \pi$,we have $r = 2$. The equation of a circle with center $(h, k)$ and radius $r$ is $(x-h)^2 + (y-k)^2 = r^2$. Substituting the center $(-2, 3)$ and radius $r = 2$: $(x - (-2))^2 + (y - 3)^2 = 2^2$ $(x + 2)^2 + (y - 3)^2 = 4$ $x^2 + 4x + 4 + y^2 - 6y + 9 = 4$ $x^2 + y^2 + 4x - 6y + 9 = 0$.

The equation of a circle with center at $(-2, 3)$ and circumference of $4 \pi$ units is

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