The equation of a plane which cuts equal inte | vedclass

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Question

(B) The intercept form of the equation of a plane is given by $\frac{x}{a} + \frac{y}{b} + \frac{z}{c} = 1$,where $a, b, c$ are the intercepts on the

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$x + y + z = 1$

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(B) The intercept form of the equation of a plane is given by $\frac{x}{a} + \frac{y}{b} + \frac{z}{c} = 1$,where $a, b, c$ are the intercepts on the $x, y, z$ axes respectively.Given that the plane cuts equal intercepts of unit length on the axes,we have $a = 1, b = 1, c = 1$.Substituting these values into the intercept form equation,we get $\frac{x}{1} + \frac{y}{1} + \frac{z}{1} = 1$.Therefore,the equation of the plane is $x + y + z = 1$.

The equation of a plane which cuts equal intercepts of unit length on the axes is:

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