The equation of a stationary wave is y = 2 s | vedclass

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(B) The given equation of the stationary wave is $ y = 2 \sin \left( \frac{\pi x}{15} \right) \cos (48 \pi t) $.Comparing this with the standard equat

Vedclass · Accepted Answer

$7.5$

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(B) The given equation of the stationary wave is $ y = 2 \sin \left( \frac{\pi x}{15} \right) \cos (48 \pi t) $.Comparing this with the standard equation $ y = A \sin(kx) \cos(\omega t) $, we get the wave number $ k = \frac{\pi}{15} $.We know that $ k = \frac{2 \pi}{\lambda} $, so $ \frac{2 \pi}{\lambda} = \frac{\pi}{15} $.Solving for wavelength $ \lambda $, we get $ \lambda = 30 $ units.The distance between a node and its consecutive antinode is given by $ d = \frac{\lambda}{4} $.Substituting the value of $ \lambda $, we get $ d = \frac{30}{4} = 7.5 $ units.

The equation of a stationary wave is $ y = 2 \sin \left( \frac{\pi x}{15} \right) \cos (48 \pi t) $. The distance between a node and its next antinode is (in $units$)

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