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(C) The given parabola is $y^2 = -4x$. Comparing this with $y^2 = -4ax$,we get $a = 1$.The focus of the parabola is $(-a, 0)$,which is $(-1, 0)$.The s

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$y + \sqrt{3}(x + 1) = 0$

Vedclass · Answer

(C) The given parabola is $y^2 = -4x$. Comparing this with $y^2 = -4ax$,we get $a = 1$.The focus of the parabola is $(-a, 0)$,which is $(-1, 0)$.The slope $m$ of the line is $	an(120^\circ) = -\sqrt{3}$.The equation of a line passing through $(x_1, y_1)$ with slope $m$ is $y - y_1 = m(x - x_1)$.Substituting the values,we get $y - 0 = -\sqrt{3}(x - (-1))$.$y = -\sqrt{3}(x + 1)$.$y + \sqrt{3}(x + 1) = 0$.

The equation of a straight line drawn through the focus of the parabola $y^2 = -4x$ at an angle of $120^\circ$ to the $x$-axis is:

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