The equation of a transverse wave propagating along a stretched string of length $80 \ cm$ is $y=1.5 \sin \{(5 \times 10^{-3} x) + 20 t\}$,where $x$ and $y$ are in $cm$ and the time $t$ is in seconds. If the mass of the string is $3 \ g$,then the tension in the string is: (in $N$)

$A$ string of length $1 \,m$ and mass $490 \,g$ is put under a tension of $25 \,N$. $A$ wave of frequency $120 \,Hz$ is sent along it. The speed of this wave is (in $\,m/s$)

$A$ transverse wave is propagating on a string. The linear mass density of the vibrating string is $10^{-3} \ kg/m$. The equation of the wave is $Y = 0.05 \sin(x + 15t)$,where $x$ and $Y$ are in meters and time $t$ is in seconds. The tension in the string is: (in $N$)

$A$ wire of length $50 \ cm$ and weighing $10 \ g$ is attached to a spring at one end and to a fixed wall at the other end. The spring has a spring constant of $50 \ N/m$ and is stretched by $1 \ cm$. If a wave pulse is produced on the string near the wall, then how much time will it take to reach the spring (in $s$)?

One end of a string is tied to the ceiling of a lift and a load is attached at the bottom end of the string. When the lift is moving upwards with an acceleration of $2.1 \,ms^{-2}$, the speed of the transverse wave at the lower end of the string is $88 \,ms^{-1}$. If the lift moves downwards with an acceleration of $1.9 \,ms^{-2}$, the speed of the transverse wave at the lower end of the string is (take $g=10 \,ms^{-2}$): (in $\,ms^{-1}$)

The mass per unit length of a uniform wire is $0.135 \, g/cm$. $A$ transverse wave of the form $y = -0.21 \sin(x + 30t)$ is produced in it,where $x$ is in meters and $t$ is in seconds. Then,the expected value of tension in the wire is $x \times 10^{-2} \, N$. The value of $x$ is (Round off to the nearest integer).