The equation of a wave is $y = 60 \sin (1200 t - 6 x)$,where '$y$' is in micron,'$t$' is in second,and '$x$' is in metre. The ratio of the maximum particle velocity to the wave velocity of wave propagation is:

The displacement of a particle is given by $y = 5 \times 10^{-4} \sin(100t - 50x)$,where $x$ is in meters and $t$ is in seconds. Find the velocity of the wave in $m/s$.

$A$ sound wave of frequency $210 \text{ Hz}$ travels with a speed of $330 \text{ ms}^{-1}$ along the positive $x$-axis. Each particle of the wave moves a distance of $10 \text{ cm}$ between the two extreme points. The equation of the displacement function $s(x, t)$ of this wave is ($x$ in metre, $t$ in second):

$A$ simple harmonic progressive wave is represented as $y = 0.03 \sin \pi (2 t - 0.01 x) \ m$. At a given instant of time,the phase difference between two particles $25 \ m$ apart is

The path difference between the two waves $y_1 = a_1 \sin \left( \omega t - \frac{2\pi x}{\lambda} \right)$ and $y_2 = a_2 \cos \left( \omega t - \frac{2\pi x}{\lambda} + \phi \right)$ is

Two sound waves having a phase difference of $60^{\circ}$ have a path difference of