The equation of the bisectors of the angle between the lines given by $3x^2+5xy+4y^2=0$ is

If the line $y=mx$ is one of the bisectors of $x^2+4xy-y^2=0$,then the value of $2m$ is:

If the angle between the pair of lines $2x^2 + 2hxy + 2y^2 - x + y - 1 = 0$ is $\tan^{-1}(3/4)$ and $h$ is a positive rational number,then the point of intersection of these two lines is

If pairs of straight lines $x^2-2 p x y-y^2=0$ and $x^2-2 q x y-y^2=0$ are such that each pair bisects the angle between the other pair,then:

If $\alpha$ represents the square of the distance between the origin and the point of intersection of the lines $x^2-y^2-x+3y-2=0$ and $\beta$ represents the product of the perpendicular distances from the origin to the pair of lines,then $\alpha \beta=$

The line $x - 2y = 0$ will be a bisector of the angle between the lines represented by the equation ${x^2} - 2hxy - 2{y^2} = 0$,if $h = $