The equation of the ellipse whose one focus is at $(4, 0)$ and whose eccentricity is $4/5$,is
- A$\frac{x^2}{3^2} + \frac{y^2}{5^2} = 1$
- B$\frac{x^2}{5^2} + \frac{y^2}{3^2} = 1$
- C$\frac{x^2}{5^2} + \frac{y^2}{4^2} = 1$
- D$\frac{x^2}{4^2} + \frac{y^2}{5^2} = 1$
Explore More
Similar Questions
The values of $c$ such that the line $y=4x+c$ touches the ellipse $\frac{x^2}{4}+\frac{y^2}{1}=1$ are
Find the equation for the ellipse that satisfies the given conditions: Foci $(\pm 3, 0)$,$a = 4$.
Medium
View SolutionIf $c \in \mathbb{R}$ be such that the line $4x - y + c = 0$ touches the ellipse $x^2 + 4y^2 = 4$,then an equation having all such values of $c$ among its roots is
The ratio of the distance of a point from a fixed point and a line $x = 9/2$ is always $2 : 3$. Then the locus of the point is
Medium
View SolutionThe equation of an ellipse,whose vertices are $(2, -2)$ and $(2, 4)$ and eccentricity is $\frac{1}{3}$,is
Difficult
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo