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(B) The given line is $x + y + 1 = 0$,which can be written as $y = -x - 1$. The slope of this line is $m_1 = -1$.The slope of a line perpendicular to

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$y - x - 1 = 0$

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(B) The given line is $x + y + 1 = 0$,which can be written as $y = -x - 1$. The slope of this line is $m_1 = -1$.The slope of a line perpendicular to this line is $m_2 = -\frac{1}{m_1} = -\frac{1}{-1} = 1$.The equation of a line with slope $m = 1$ passing through the point $(x_1, y_1) = (1, 2)$ is given by $y - y_1 = m(x - x_1)$.Substituting the values,we get $y - 2 = 1(x - 1)$.Simplifying this,we get $y - 2 = x - 1$,which results in $y - x - 1 = 0$.

The equation of the line passing through the point $(1, 2)$ and perpendicular to the line $x + y + 1 = 0$ is

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