(D) Given the circle $x^2+y^2=9$ and the line $x+y=3$. To find the equation of the pair of lines joining the origin to the intersection points,we homo

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(D) Given the circle $x^2+y^2=9$ and the line $x+y=3$. To find the equation of the pair of lines joining the origin to the intersection points,we homogenize the equation of the circle using the line equation. Since $x+y=3$,we have $\frac{x+y}{3} = 1$. Substituting this into the circle equation: $x^2+y^2 = 9(1)^2$ $x^2+y^2 = 9\left(\frac{x+y}{3}\right)^2$ $x^2+y^2 = 9\left(\frac{(x+y)^2}{9}\right)$ $x^2+y^2 = (x+y)^2$ $x^2+y^2 = x^2+y^2+2xy$ $2xy = 0$ $xy = 0$

Class 11 Mathematics Pair of straight lines Equation of lines joining the origin to the point of intersection of a curve and a line and Distance between the pair of lines

Medium

The equation of the pair of lines joining the origin to the points of intersection of $x^2+y^2=9$ and $x+y=3$ is:

AP EAMCET 2016 All AP EAMCET

A
$x^2+(3-y)^2=9$
B
$(3+y)^2+y^2=9$
C
$x^2 - y^2 = 9$
D
$xy = 0$

Explore More

Browse All

Question Bank

All Subjects

Class 11 Questions

Class 11

Mathematics Questions

Chapter

Pair of straight lines

Subtopic

Equation of lines joining the origin to the point of intersection of a curve and a line and Distance between the pair of lines

Previous Year

AP EAMCET 2016 Paper All AP EAMCET years →

The acute angle formed between the lines joining the origin to the points of intersection of the curves $x^2 + y^2 - 2x - 1 = 0$ and $x + y = 1$ is

Difficult

View Solution

The pair of straight lines joining the origin to the points of intersection of the line $y = 2\sqrt{2}x + c$ and the circle $x^2 + y^2 = 2$ are at right angles,if

Difficult

View Solution

The lines joining the origin to the points of intersection of the curves $ax^2 + 2hxy + by^2 + 2gx = 0$ and $a'x^2 + 2h'xy + b'y^2 + 2g'x = 0$ will be mutually perpendicular,if

Difficult

View Solution

The distance between the lines represented by the equation $x^2 + 2\sqrt{3}xy + 3y^2 - 3x - 3\sqrt{3}y - 4 = 0$ is

Medium

View Solution

Two lines are given by $(x - 2y)^2 + k(x - 2y) = 0$. The value of $k$ so that the distance between them is $3$,is

Medium

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

The equation of the pair of lines joining the origin to the points of intersection of $x^2+y^2=9$ and $x+y=3$ is:

Similar Questions

The acute angle formed between the lines joining the origin to the points of intersection of the curves $x^2 + y^2 - 2x - 1 = 0$ and $x + y = 1$ is

The pair of straight lines joining the origin to the points of intersection of the line $y = 2\sqrt{2}x + c$ and the circle $x^2 + y^2 = 2$ are at right angles,if

The lines joining the origin to the points of intersection of the curves $ax^2 + 2hxy + by^2 + 2gx = 0$ and $a'x^2 + 2h'xy + b'y^2 + 2g'x = 0$ will be mutually perpendicular,if

The distance between the lines represented by the equation $x^2 + 2\sqrt{3}xy + 3y^2 - 3x - 3\sqrt{3}y - 4 = 0$ is

Two lines are given by $(x - 2y)^2 + k(x - 2y) = 0$. The value of $k$ so that the distance between them is $3$,is

Vedclass Test Series

Exam Paper Generator

Online Exam Module