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(B) The equation of a plane passing through the intersection of two planes $P_1 = 0$ and $P_2 = 0$ is given by $P_1 + \lambda P_2 = 0$.Here,the planes

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$17x + 14y + 11z = 0$

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(B) The equation of a plane passing through the intersection of two planes $P_1 = 0$ and $P_2 = 0$ is given by $P_1 + \lambda P_2 = 0$.Here,the planes are $x + 2y + 3z - 4 = 0$ and $4x + 3y + 2z + 1 = 0$.So,the equation of the required plane is $(x + 2y + 3z - 4) + \lambda(4x + 3y + 2z + 1) = 0$.Since this plane passes through the origin $(0, 0, 0)$,we substitute $x=0, y=0, z=0$ into the equation:$(0 + 0 + 0 - 4) + \lambda(0 + 0 + 0 + 1) = 0$$-4 + \lambda = 0 \implies \lambda = 4$.Substituting $\lambda = 4$ back into the equation:$(x + 2y + 3z - 4) + 4(4x + 3y + 2z + 1) = 0$$x + 2y + 3z - 4 + 16x + 12y + 8z + 4 = 0$$17x + 14y + 11z = 0$.

The equation of the plane through the intersection of the planes $x + 2y + 3z - 4 = 0$ and $4x + 3y + 2z + 1 = 0$ and passing through the origin is:

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