The equation of the radical axis of the pair of circles $7x^2+7y^2-7x+14y+18=0$ and $4x^2+4y^2-7x+8y+20=0$ is

  • A
    $x-2y-5=0$
  • B
    $2x-y+5=0$
  • C
    $21x-68=0$
  • D
    $23x-68=0$

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Similar Questions

The co-axial system of circles given by ${x^2} + {y^2} + 2gx + c = 0$ for $c < 0$ represents

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The equation of the circle which intersects circles ${x^2} + {y^2} + x + 2y + 3 = 0$,${x^2} + {y^2} + 2x + 4y + 5 = 0$,and ${x^2} + {y^2} - 7x - 8y - 9 = 0$ at right angles is:

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In List-$I$,a pair of circles is given in $A$,$B$,$C$ and in List-$II$,the angle between those pairs of circles is given. Match the items from List-$I$ to List-$II$.
List-$I$ List-$II$
$(A)$ $(x-2)^2+y^2=2$,$(x-2)^2+(y-1)^2=1$ $I.$ $90^{\circ}$
$(B)$ $x^2+y^2-6x-6y+9=0$,$x^2+y^2-4x+4y-9=0$ $II.$ $135^{\circ}$
$(C)$ $x^2+y^2+4x-14y+28=0$,$x^2+y^2+4x-5=0$ $III.$ $60^{\circ}$
$IV.$ $30^{\circ}$

The correct matching is

If the circles $x^2 + y^2 = 4$ and $x^2 + y^2 - 10x + \lambda = 0$ touch externally,then $\lambda$ is equal to:

The equation of the radical axis of the circles $x^2+y^2+4x+6y+7=0$ and $4x^2+4y^2+8x+12y-9=0$ is:

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