The equivalent capacitance between $A$ and $B$ is (in $\mu F$):

The total charge on the system of capacitors with capacitances $C_{1} = 1\,\mu F$,$C_{2} = 2\,\mu F$,$C_{3} = 4\,\mu F$,and $C_{4} = 3\,\mu F$ connected in parallel is $......\,\mu C$. (Assume a battery of $20\,V$ is connected to the combination.)

Three capacitors $3 \mu F$, $6 \mu F$, and $6 \mu F$ are connected in series to a source of $120 V$. The potential difference, in volts, across the $3 \mu F$ capacitor will be:

Eight capacitors,each of capacitance $C$,are connected as shown in the figure. The effective capacitance between $A$ and $B$ is

Three capacitors each of $6\,\mu F$ are available. The minimum and maximum capacitances which may be obtained are

Two capacitors of capacitance $2\ \mu F$ and $3\ \mu F$ are joined in series. The outer plate of the first capacitor is at $1000\ V$ and the outer plate of the second capacitor is earthed (grounded). The potential on the inner plates of each capacitor will be: (in $V$)