The equivalent capacitance between A and B in | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The given circuit is an infinite ladder network. Due to the symmetry of the circuit,the potential difference across the vertical $1 \mu F$ capacit

Vedclass · Accepted Answer

$\frac{4}{3} \mu F$

Vedclass · Answer

(D) The given circuit is an infinite ladder network. Due to the symmetry of the circuit,the potential difference across the vertical $1 \mu F$ capacitors is zero. Thus,these capacitors can be removed from the circuit.After removing the vertical capacitors,the circuit simplifies into two parallel branches,each containing an infinite series of capacitors with values $1 \mu F, 3 \mu F, 9 \mu F, 27 \mu F, \dots$ in a geometric progression.Let the equivalent capacitance of one branch be $C'$. The reciprocal of the equivalent capacitance for one branch is given by the sum of the reciprocals of the individual capacitors:$\frac{1}{C'} = \frac{1}{1} + \frac{1}{3} + \frac{1}{9} + \frac{1}{27} + \dots$This is an infinite geometric series with the first term $a = 1$ and common ratio $r = \frac{1}{3}$.The sum of an infinite geometric series is $S = \frac{a}{1-r}$.$\frac{1}{C'} = \frac{1}{1 - \frac{1}{3}} = \frac{1}{\frac{2}{3}} = \frac{3}{2} \mu F^{-1}$.Therefore,$C' = \frac{2}{3} \mu F$.Since there are two such branches connected in parallel between $A$ and $B$,the total equivalent capacitance $C_{AB}$ is:$C_{AB} = C' + C' = 2 	imes \frac{2}{3} \mu F = \frac{4}{3} \mu F$.

The equivalent capacitance between $A$ and $B$ in the given figure is

Similar Questions

Four metallic plates, each with a surface area of one side $A$, are placed at a distance $d$ from each other. The plates are connected as shown in the figure. The capacitance of the system between $a$ and $b$ is

In the circuit shown,the potential difference across the $4.5 \mu F$ capacitor is

Find the equivalent capacitance across $A$ and $B$ in $\mu F$.

Two capacitors of capacitances $1 \ \mu F$ and $2 \ \mu F$ can separately withstand potentials of $6 \ kV$ and $4 \ kV$ respectively. The total potential they together can withstand when they are connected in series is (in $kV$)

The figure shows the charge $(q)$ versus voltage $(V)$ graph for series and parallel combinations of two given capacitors. The capacitances are:

Vedclass Test Series

Exam Paper Generator

Online Exam Module