The equivalent capacitance of the combination shown in the figure is:

  • A
    $C$
  • B
    $2C$
  • C
    $\frac{3}{2}C$
  • D
    $\frac{C}{2}$

Explore More

Similar Questions

The minimum number of capacitors each of $2 \ \mu F$ required to make a circuit with an equivalent capacitance of $5 \ \mu F$ is

Find the equivalent capacitance between points $A$ and $B$ in the given figure. (in $\mu F$)

The potential at the point $B$ in the given figure is . . . . . . $V$.

Four capacitors are connected as shown in the adjoining figure. The capacitance of each is $8\,\mu F$. The equivalent capacitance between the points $A$ and $B$ will be......$\mu F$.

In the given circuit,what is the potential difference across the $4.5\ \mu F$ capacitor in $V$?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo